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Given the code below:
01 function Person() {
02 this.firstName = ' John ' ;
03 }
04
05 Person.proto = {
06 job: x = > ' Developer '
07 });
08
09 const myFather = new Person();
10 const result = myFather.firstName + ' ' + myFather.job();
What is the value of result when line 10 executes?
|
A
|
|---|
|
Explanation
Person.proto is being set, but JavaScript uses Person.prototype for the prototype chain, not Person.proto. Therefore, job is not on Person.prototype, and instances of Person do not have job via prototype. myFather is created with new Person(), so: myFather.firstName is ' John ' . myFather.job is undefined. Attempting to call myFather.job() results in: TypeError: myFather.job is not a function So option A is correct. |
Corrected code:
function Person() {
this.firstName = " John " ;
}
Person.prototype = {
job: x = > " Developer "
};
const myFather = new Person();
const result = myFather.firstName + " " + myFather.job();
What is the value of result after line 10 executes?
|
A
|
|---|
|
Explanation
The verified answer is A . This constructor function runs when new Person() is called: function Person() { this.firstName = " John " ; } So this line: const myFather = new Person(); creates an object like this: { firstName: " John " } Then the prototype is assigned a method named job: Person.prototype = { job: x = > " Developer " }; Because myFather is created from Person, it can access properties and methods from Person.prototype. So: myFather.firstName returns: " John " And: myFather.job() returns: " Developer " Therefore: const result = myFather.firstName + " " + myFather.job(); becomes: const result = " John " + " " + " Developer " ; Final value: " John Developer " Option B is incorrect because job() returns " Developer " , not undefined. Option C is incorrect because job exists on Person.prototype, so it is callable. Option D is incorrect because firstName is assigned inside the constructor. Therefore, the verified answer is A . |
A developer has a fizzbuzz function that, when passed in a number, returns the following:
' fizz ' if the number is divisible by 3.
' buzz ' if the number is divisible by 5.
' fizzbuzz ' if the number is divisible by both 3 and 5.
Empty string if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?
|
B, D
|
|---|
|
Explanation
The correct answers are B and D . A strong test case checks whether the actual output matches the expected behavior of the function. For Option B : let res = fizzbuzz(15); console.assert(res === ' fizzbuzz ' ); The number 15 is divisible by both 3 and 5: 15 % 3 === 0 15 % 5 === 0 So the correct return value is: ' fizzbuzz ' That makes option B a valid test. For Option D : let res = fizzbuzz(Infinity); console.assert(res === ' ' ); Infinity is not a normal finite divisible number. In JavaScript: Infinity % 3 Infinity % 5 produce NaN, and comparisons such as: Infinity % 3 === 0 are false. So a typical fizzbuzz implementation would not treat Infinity as divisible by 3 or 5, meaning it should return: ' ' That makes option D a valid test for the “neither divisible by 3 nor 5” path. Now compare the incorrect options: Option A is wrong because: fizzbuzz(3) should return: ' fizz ' not: ' buzz ' Option C is wrong because the function specification says the function returns strings such as ' fizz ' , ' buzz ' , ' fizzbuzz ' , or ' ' . It does not say the function returns numeric NaN. So this assertion is not appropriate: console.assert(isNaN(res)); Therefore, the verified answers are B and D . |
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Find answers to the most common questions about the Salesforce JavaScript-Developer-I exam, including what it is, how to prepare, and how it can boost your career.
The Salesforce JavaScript-Developer-I certification is a globally-acknowledged credential that is awarded to candidates who pass this certification exam by obtaining the required passing score. This credential attests and validates the candidates' knowledge and hands-on skills in domains covered in the Salesforce JavaScript-Developer-I certification syllabus. The Salesforce JavaScript-Developer-I certified professionals with their verified proficiency and expertise are trusted and welcomed by hiring managers all over the world to perform leading roles in organizations. The success in Salesforce JavaScript-Developer-I certification exam can be ensured only with a combination of clear knowledge on all exam domains and securing the required practical training. Like any other credential, Salesforce JavaScript-Developer-I certification may require periodic renewal to stay current with new innovations in the concerned domains.